Question

The shortest side of a polygon of area 196 sq. in. is 4 in. long. Find the area of a similar polygon whose shortest side is 8 in. long.

Answer 1

Step-by-step explanation:

For similar shapes, the ratio of the areas is proportional to the square of the length ratio for any corresponding side.

Therefore,

Area of the polygon having shortest side 4 in : Area of the polygon having shortest side 8 in = $(\frac{4}{8})^{2}$

$=>\frac{196}{Area\:of\:the\:polygon\:whose\:shortest\:side\:is\:8\:in}=\frac{16}{64}\\\\=>Area\:of\:the\:polygon\:whose\:shortest\:side\:is\:8\:in=4*196\\=>Area\:of\:the\:polygon\:whose\:shortest\:side\:is\:8\:in=784\:inch^{2}$

________________

//Hope this will Helped You//

//Please mark it as Brainliest//

#BAL  #ANSWERWITHQUALITY