Question

the shortest side of a right angled triangle ia 6 cm shorter than it's hypotenuae . the difference between in lengths of perpendicular two sides is 3 cm . find the lenghths of all it&s side. if anyone gives wrong answer then I will report you​

Answer 1

Answer:

Step-by-step explanation:

Let the base be p

Hypotenuse = 2p +6

Perpendicular = 2p + 4

By Pythagoras theoram

(2p+6)^2 = (2p+4)^2 +p^2

=> 4p^2 +36 + 24p = 4p^2 + 16 +16p +p^2

=> 36+ 24p = p^2 + 16p + 16

=> p^2 - 8p - 20 = 0

=> p^2 - 10p +2p - 20 = 0

=> p(p-10) +2(p-10) = 0

=> (p-10)(p+2) = 0

p = 10 and - 2

Length can't be negative

So,

p = 10

Base = 10

Perpendicular = 24

Hypotenuse = 26

Hope it help you

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Answer 2

Answer:

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