Question

The side AB & AC of triangle ABC are produced to points P & Q respectively
angle CBP & angle BCQ respectively meet at O, then prove that angle BOC ½(y+z). ​

Answer 1

Answer:

if bisectors BO and CO of angle CBE and angle BCD respectively meet at point O, then prove that angle BOC =90°-1/ 2 ...

The bisectors of exterior angles at B and C of triangle ABC meet at O. Prove that angle BOC = 90 degree -1/2 angle A ...