The side BA and CD of a quadrilateral ABCD are produced as shown in figure. Prove that a+b = x+y
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in triangle abd we have
angle abd +adb=b....(1)
angle cbd+angle cdb=a.....(2)
adding (1) and (2)
x+y=a+b
in triangle abd we have
angle abd +adb=b....(1)
angle cbd+angle cdb=a.....(2)
adding (1) and (2)
x+y=a+b
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