The side of a regular dodecagon is 2 cm. The radius of the circumscribed circle in cms ?
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Regular Dodecagon has 12 sides. The external angle = 360/12 = 30°
The internal angle = 150°.
If we join one side AB with center O, then AO=BO= Circumradius = R.
ΔABO is isosceles. Angle between two radii AO & BO = 30° . We apply cosine rule.
a^2 = R^2 + R^2 - 2 R * R * cos30°
= R^2 ( 2 - √3)
R = a √(2+√3) = 3.863 cm
The internal angle = 150°.
If we join one side AB with center O, then AO=BO= Circumradius = R.
ΔABO is isosceles. Angle between two radii AO & BO = 30° . We apply cosine rule.
a^2 = R^2 + R^2 - 2 R * R * cos30°
= R^2 ( 2 - √3)
R = a √(2+√3) = 3.863 cm
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Regular Dodecagon has 12 sides. The external angle = 360/12 = 30°
The internal angle = 150°.
If we join one side AB with center O, then AO=BO= Circumradius = R.
ΔABO is isosceles. Angle between two radii AO & BO = 30° . We apply cosine rule.
a^2 = R^2 + R^2 - 2 R * R * cos30°
= R^2 ( 2 - √3)
R = a √(2+√3) = 3.863 cm
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