the side of a regular pentagonal shape matalic wires measures 12cm. If that stretched out and into a rectangle of width 12cm what will be the area of the new rectangle?
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Side of regular Pentagon= 12 cm
perimeter = 12×5 = 60cm
now it is converted to a rectangle of width 12cm
let its length = l
Perimeter= 2(l+12)
60 = 2(l+12)
60 = 2l + 24
2l = 60-24 = 36
l = 36/2 = 18cm
length of rectangle= 18cm
width of rectangle = 12 cm
area = length×width = 18×12 = 216 cm^2
area of new rectangle is 216 cm^2
perimeter = 12×5 = 60cm
now it is converted to a rectangle of width 12cm
let its length = l
Perimeter= 2(l+12)
60 = 2(l+12)
60 = 2l + 24
2l = 60-24 = 36
l = 36/2 = 18cm
length of rectangle= 18cm
width of rectangle = 12 cm
area = length×width = 18×12 = 216 cm^2
area of new rectangle is 216 cm^2
pboveralls:
thank you a lot TPS. Genuis!
you are welcome:)
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total length=5*12=60cm
rectangle of side a, 12cm=2a+12+12=60
a=18cm
area=a*12=18*12=216 cm²
rectangle of side a, 12cm=2a+12+12=60
a=18cm
area=a*12=18*12=216 cm²
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