Question

The side of a right-angled triangle containing the right-angled are 14m qnd 7m.find the area of triangle

Answer 1

Answer:

49 square meters

Step-by-step explanation:

Area of triangle= 0.5 * base* height

=0.5* 14*7

=49 square meters

hope this helps!

Answer 2

we have,

sides of a right angled triangle containing right angle are 14m and 7m respectively.

Hence, perpendicular (altitude) = 14m.

and,base = 7m.


we know,


area of a right angled triangle =

$\frac{1}{2} \times base \times height$
=
$\frac{1}{2} \times 7 \times 14 \\ = 7 \times 7 \\ = 49 {m}^{2}$

Regards

KSHITIJ