The side of a square decreased by 20%. what percent its area will be decreased?
Answers
Answered by
4
Let the side of square be a
Area = a^2
Side of new square formed = a - 20 % of a
= a - 20a/100
= a - a/5
= 4a/5
Area of new square = ( 4a/5)^2 = 16a^2 / 25
Decrease in Area = Original Area - New Area
= a^2 - 16a^2 /25
= 9a^2 / 25
Percentage of Increase = increase in Area × 100 / Original Area
= ( 9a^2 /25) × 100 / a^2
= 9a^2 × 4 / a^2
= 36 %
Area = a^2
Side of new square formed = a - 20 % of a
= a - 20a/100
= a - a/5
= 4a/5
Area of new square = ( 4a/5)^2 = 16a^2 / 25
Decrease in Area = Original Area - New Area
= a^2 - 16a^2 /25
= 9a^2 / 25
Percentage of Increase = increase in Area × 100 / Original Area
= ( 9a^2 /25) × 100 / a^2
= 9a^2 × 4 / a^2
= 36 %
Answered by
3
Let the side is x
Area = x^2
Now the side decreased by 20%
side = x-20%of x
= 4x/5
Area = (4x/5)^2
Decrease in area = x^2 - (4x/5)^2
= 9x^2/25
Percentage decrease in area = (9x^2/25) x 100/x^2
= 36%
Area = x^2
Now the side decreased by 20%
side = x-20%of x
= 4x/5
Area = (4x/5)^2
Decrease in area = x^2 - (4x/5)^2
= 9x^2/25
Percentage decrease in area = (9x^2/25) x 100/x^2
= 36%
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