The side of a square exceeds the side of
another square by 5 cm. The difference of
their areas is 325 sq. cm. Find the sides of
each square.
Answers
Step-by-step explanation:
1
A side of square exceeds the side of another square by 4 cm and the sum of area of two squares is 400 cm sq. How to find the dimensions of the squares?
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Ruhaizat Ooi
Answered September 24, 2018
Let the sides of Square A be “x” cm,
and the sides of Square B be “x + 4” cm.
Hence, sum of area of two squares A abd B are :
x^2 + (x +4)^2 = 400
x^2 + (x^2 + 8x + 16) = 400
2x^2 + 8x + 16 = 400
x^2 + 4x + 8 = 200
x^2 + 4x - 192 = 0
(x - 12)(x + 16) = 0
therefore, x = 12, or -16.
Substitute x = 12 into first equation, we have
144 + (16)^2 = 400
144 + 256 = 400 QED.
dimension of Square A is 12cm
dimension of Square B is 16cm
Answer:
Side of square 1: 30cm
Side of square 2: 30 + 5= 35cm
Step-by-step explanation:
Refer to the image below:
