Physics, asked by singnavneet020, 10 months ago

the side of a square plot is 204 M Wide Road is constructed along its boundary outside the plot find the area of the road cost of constructing it at rupees 15 per square metre​

Answers

Answered by Shubhendu8898
2

Answer: 5760

Explanation:

Consider the given  plot and road as shown in the picture.

Sides of  square plot(ABCD) = 20M

Sides of square road(PQRS) = 20 + 4 + 4

                                               = 28 M

We know that area of square field = (Side)²

So,

Area of sqaure ABCD = (20m)²

                                    = 400 m²

Area of square PQRS = (28m)²

                                    = 784 m²  

Clearly,

Area of Road = Area(PQRS) - Area(ABCD)

                       = 784m² - 400m²

                       = 384 m²  

Now,

Cost of constructing this area at the rate of rupees 15 per square metre will be,

Cost = 384 × 15

        = ₹5760  

Attachments:
Answered by Fatimakincsem
1

The are of road is 382 m^2 and the total cost of construction is 5,730 Rs.

Explanation:

We are given that:

Area of the Square Plot = (side)^2 = (20)^2 = 400 m^2

As per the question statement:

A 4 m wide road is constructed along its boundary outside the plot.

So the area of the outer square plot =(side)^2 = (20 + 4 + 4)^2 = (28)2 = 782 m^2

Area of the road = 782  - 400 =  382 m^2

Cost per unit area = 15 Rs

Total cost = 382 x 15 = 5,730 Rs

Thus the are of road is 382 m^2 and the total cost of construction is 5,730 Rs.

Also learn more

A rectangular lawn 70 m by 50 m has two roads each 5 m wide,running through its middle .One parallel to its length and other parallel to its breadth . Find the cost of constructing the roads at ₹120 per m^2 ?

https://brainly.in/question/2248347

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