the side of a square plot is 204 M Wide Road is constructed along its boundary outside the plot find the area of the road cost of constructing it at rupees 15 per square metre
Answers
Answer: 5760
Explanation:
Consider the given plot and road as shown in the picture.
Sides of square plot(ABCD) = 20M
Sides of square road(PQRS) = 20 + 4 + 4
= 28 M
We know that area of square field = (Side)²
So,
Area of sqaure ABCD = (20m)²
= 400 m²
Area of square PQRS = (28m)²
= 784 m²
Clearly,
Area of Road = Area(PQRS) - Area(ABCD)
= 784m² - 400m²
= 384 m²
Now,
Cost of constructing this area at the rate of rupees 15 per square metre will be,
Cost = 384 × 15
= ₹5760
The are of road is 382 m^2 and the total cost of construction is 5,730 Rs.
Explanation:
We are given that:
Area of the Square Plot = (side)^2 = (20)^2 = 400 m^2
As per the question statement:
A 4 m wide road is constructed along its boundary outside the plot.
So the area of the outer square plot =(side)^2 = (20 + 4 + 4)^2 = (28)2 = 782 m^2
Area of the road = 782 - 400 = 382 m^2
Cost per unit area = 15 Rs
Total cost = 382 x 15 = 5,730 Rs
Thus the are of road is 382 m^2 and the total cost of construction is 5,730 Rs.
Also learn more
A rectangular lawn 70 m by 50 m has two roads each 5 m wide,running through its middle .One parallel to its length and other parallel to its breadth . Find the cost of constructing the roads at ₹120 per m^2 ?
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