Question

the side of a tectangle are in the ratio 7:2 and its perimeter is 108 cm .find its length and breadth ,and also find its area
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Answer 1

Answer:

length is 35 cm

breadth is 10 cm

Step-by-step explanation:

let the common multiple be x,

ratio 7:2

so,

7x:2x

length = 7x

breadth =2x

perimeter of a rectangle = 108 cm

2(l+b) = 108

2(7x+2x) = 108

2(9x) = 108

9x= 108/2

9x= 54

x = 54/9

x=5

length is 7*5 that is 35

breadth is 2*5 that is 10

Answer 2

let the length be= 7x

and the breadth = 2x

Perimeter of rectangle = 108cm

Perimeter of Rectangle = 2(Length + Breadth )

108 = 2(7x + 2x)

108 = 2(9x)

108/2= 9x

54 = 9x

x = 54/9

x = 6

Length of the rectangle = 7x = 7× 6= 42 cm

Breadth of the rectangle= 2x = 2× 6 = 12 cm

Then area of rectangle = Length × Breadth

= (42×12)

= 504 sq.cm

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