the side of a triangle are 16 cm 30 cm and 34 CM its area is
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by herons fourmula
√s(s-16)(s-30)(s-34)
s=16+30+34/2
√s(s-16)(s-30)(s-34)
s=16+30+34/2
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17
Answer:
Here is your answer ✓ ✓ ✓ ✓
First side ( A ) = 16 cm
Second side ( B ) = 30 cm
And,
Third side ( C ) = 34 cm
Semi perimeter ( S ) = A + B + C /2 = 16 + 30 + 34/2 = 80/2 = 40 cm
Therefore,
( S - A ) = ( 40 - 16 ) = 24 cm
( S - B ) = ( 40 - 30 ) = 10 cm
And,
( S - C ) = ( 40 - 34 ) = 6 cm.
Therefore,
Area of the triangle = √S (S - A ) ( S - B ) ( S - C ) => √ 40 × 24 × 10 × 6
=> ✓ 57600 = 240 cm².
Hence,
Area of triangle = 240 cm².
☺ Hope it will help you ☺
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