Question

The side of a triangle are 21 cm,17 cm and 10 cm.Calculate its area and length of the height on the longest side?

Answer 1

area is root s (s-a)(s-b)(s-c)
s=21+17+10/2=48/2cm=24cm
area=
$\sqrt{24(24 - 21)(24 - 17)(24 - 10)}$


that is
$\sqrt{7 \times 4\times 3 \times 7 \times 7 \times 2}$

7×2root 42
14root42cm2
it is equal to 1/2×21×height
this may help u