the side of a triangle are in the ratio 2:3:4 if the perimeter is 72 cm. find its side
Answers
Answered by
31
Let the sides be 2x, 3x, and 4x.
2x + 3x+ 4x = 72
9x = 72
x = 8
sides = 2x = 2(8) = 16
3x = 3(8) = 24
4x = 4(8) = 32
Sides are 16 cm, 24 cm, and 32 cm.
2x + 3x+ 4x = 72
9x = 72
x = 8
sides = 2x = 2(8) = 16
3x = 3(8) = 24
4x = 4(8) = 32
Sides are 16 cm, 24 cm, and 32 cm.
Answered by
18
Let the sides of triangle be 2x, 3x and 4x.
Perimeter of triangle = 72 cm
A/q,
Sum of all sides = Perimeter of triangle.
➡ 2x + 3x + 4x = 72
➡ 9x = 72
➡ x = 72/9
➡ x = 8
Sides of triangle :-
➡ 2x = 2(8) = 16 cm
➡ 3x = 3(8) = 24 cm
➡ 4x = 4(8) = 32 cm.
Hope it will help you !!!
Perimeter of triangle = 72 cm
A/q,
Sum of all sides = Perimeter of triangle.
➡ 2x + 3x + 4x = 72
➡ 9x = 72
➡ x = 72/9
➡ x = 8
Sides of triangle :-
➡ 2x = 2(8) = 16 cm
➡ 3x = 3(8) = 24 cm
➡ 4x = 4(8) = 32 cm.
Hope it will help you !!!
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