Question

the side of a triangle are X square + 20 + 2 X square + 6 X + 7 and 5 x square - 4 x + 15 what its perimeter ​

Answer 1

Given,

$\bf \: {1}^{st} \: side \: of \: triangle = {x}^{2} + 20 \\ \bf {2}^{nd} \: side \: of \: triangle = \small{{2x}^{2} + 6x + 7} \\ \bf{3}^{rd} \: side \: of \: triangle = \small{ {5x}^{2} - 4x + 15}$

Now,

$\large \sf \: \: \: \: Perimeter \: of \: this \: triangle \\ \\ \sf \small= > ( {x}^{2} + 20) + ( {2x}^{2} + 6x + 7 ) + ( {5x}^{2} - 4x + 15) \\ \sf \small = > {x}^{2} + 20 + {2x}^{2} + 6x + 7 + {5x}^{2} - 4x + 15 \\ \sf = > (\red{{8x}^{2} + 2x + 42}) \: unit$

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