Question

The side of a triangle is 12 cm 11 cm and 15 cm . Find the area of traingle

Answer 1

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Here is your solution...☺

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⚫ Side of a triangle = 12cm, 11cm and 15cm.

$semiperimeter \: = \frac{( \: 12 + 11 + 15)cm}{2}$
= 38/2
=19.

Area of triangle =

$= \sqrt{s(s - a)(s - b)(s - c)}$
$= \sqrt{19(19 - 12)(19 - 11)(19 - 15)}$
$= \sqrt{19(7)(8)(4)}$
$= \sqrt{4256}$
= 65.23cm²

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✴ Hence, the area of given triangle = 65.23cm².

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