Question

the side of a tringale are in the ratio 1/3:1/4:1/5and its permeteris 94cm. the length of the smallest side is

Answer 1

Let d sides be x/3,x/4,x/5.


x/3+x/4+x/5 = 94
(20x+15x+12x)=94*60
47x=94*60
x=120



length of smallest side i.e. x/5 =24.

Answer 2

Hi ,  Let a , b , c are the sides of a   triangle .

 It is given that ,  

a : b : c = 1/3 : 1/4 : 1/5

 Multiply each ratio with

60 ,  we get  

a : b : c = 60/3:60/4:60/5

 a : b : c = 20 : 15 : 12

 Let a = 20x ,  b = 15x ,  c = 12x ,

 Perimeter = 94 m

 a + b + c = 94

 20x + 15x + 12x = 94

 47x = 94  

x = 94/47

 x = 2  

Therefore ,

 a = 20x = 20 × 2 = 40 m

 b = 15x = 15 × 2 = 30 m

 c = 12x= 12 × 2 = 24 m

 Least side length = c = 24 m

 I hope this helps you.  : )