Question

the side of rectangle is 3:4. the area is 432 .find its dimention

Answer 1

area=length*width

A=l*w

l=length

(3/4)l=width

A=l*w

432=(l)*(3/4)l

432=(3/4)*l2

multiply both sides by 4/3

(4/3)(432)=(4/3)(3/4)(l2)

576=l2

take the square root of both sides

√576=√l2

24=l

l=24 feet for the length

(3/4)(24)=18 feet for the width

check: 432=24*18=432

Answer 2

area=length*width

A=l*w

l=length

(3/4)l=width

A=l*w

432=(l)*(3/4)l

432=(3/4)*l2

multiply both sides by 4/3

(4/3)(432)=(4/3)(3/4)(l2)

576=l2

take the square root of both sides

√576=√l2

24=l

l=24 feet for the length

(3/4)(24)=18 feet for the width

check: 432=24*18=432

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