Question

the side of rhombus is 10cm and one diagonal measures 12cm .find the length of the other diagonals . the answer would be 16 cm plzz

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Answer 1

Answer:

Here is your answer

So , when the two diagonals intersect , four right angled triangles are formed . Lets take one right angled triangle . => AB = 6 . Hence , the length of the other diagonal is ( 2 * 6 ) cm = 12 cm .

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Answer 2

Step-by-step explanation:

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In ΔABC, $AC^{2} = AB^{2} + BC^{2}$ (since the diagonals of a rhombus bisect each other)

⇒$10^{2} = AB^{2}+ 6^{2}$

⇒$10^{2} - 6^{2} =AB^{2}$

⇒$\sqrt{100 - 36} = AB$

⇒$AB= \sqrt{64} =8cm$

OTHER diagonal = AB X 2 = 16cm