the side of rhombus is 26m and length of one of its diagonals is 20m. the area of the rhombus is
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A rhombus has 4 equal sides, each would be 26m.
One of the diagonals is 20m...this is bisected by the other diagonal into 10m segs.
The diagonals of a rhombus intersect at right angles. Use the Pythagorean Theorem to find the length of the other diagonal...
10² + b² = 26²
100 + b² = 676
b² = 576
b = 24
This is of course the length of just one segment, the diagonal is 48m.
Area of rhombus= 1/2*d1*d2
=1/2*20*48
=480m²
One of the diagonals is 20m...this is bisected by the other diagonal into 10m segs.
The diagonals of a rhombus intersect at right angles. Use the Pythagorean Theorem to find the length of the other diagonal...
10² + b² = 26²
100 + b² = 676
b² = 576
b = 24
This is of course the length of just one segment, the diagonal is 48m.
Area of rhombus= 1/2*d1*d2
=1/2*20*48
=480m²
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