Question

the side of the parallelo gram whose area is 170.5 square cm and the height is 7.75 cm​

Answer 1

$\huge\bf{SOLUTION:-}$

Given:-

• The height of parallelogram=7.75cm

• The area of parallelogram
• $\sf \implies 170.5cm{}^{2}$

TO FIND:-

we have to find the side of parallelogram

$\bf\underline{According \:to\: Question:-}$

$\tt Area\:of\: parallelogram=base\times height$

• Base=side

$\tt Area\:of\: parallelogram=Base\times height\\ \\ \sf\leadsto we\:have \:\:height =7.75cm\\ :\:\:\:\:\tt area=170.5cm{}^{2}\\ \\ \tt\rightarrow 170.5cm{}^{2}=7.75cm\times base\\ \\ \tt\rightarrow \cancel{\frac{170.5cm{}^{2}}{7.75cm}}=base\\ \\ \tt\implies 22.733cm=base$

The base of parallelogram is 22.733cm

Let's verify:-

$\sf Area\:of\: parallelogram=B\times h\\ \\ \sf 170.5=7.75\times 22.73\\ \\ \sf\leadsto 170.5=170.497\\ \\ \tt By\: estimation\\ \\ \sf\implies or\: 170.5=170.5$

L.H.S=R.H.S (Hence ,verified)

$\mathfrak {Side\:of\: parallelogram=22.733cm}$

#BAL

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