the side of the square farm is hactometer find how many rectangular plot of length 20 m and breadth 10 meter can be cut from the farm?
Answers
Answer:
5000 rectangular plots can be cut from the square farm.
Step-by-step explanation:
There's a minor mistake in the question, let me correct it first.
Corrected Question: The side of the square farm is hectometer find how many rectangular plot of length 20m and breadth 10cm can be cut from the farm?
Consider the provide information.
As per the provided information in the given question, we've been given that the side of the square farm is 1 hectometer and rectangular plot of length 20m and breadth 10cm. With this information, we have been asked to find, how many rectangular plots can be cut from the square farm?
The given values are,
Side of square, a = 1 hm = 10000cm
Length of rectangle, l = 20m = 2000cm
Breadth of rectangle, b = 10cm
We know that, the area of a square is the product of the two sides of the square. It is also known as squares of the sides. i.e.
→ Area of square = a²
By substituting the known value in the formula, we get:
→ Area of square = (10000)²
→ Area of square = 100000000 cm²
Now we know that, the area of a rectangle is the product of length and breadth. i.e.
→ Area of rectangle = length * breadth
By substituting the known values in the formula, we get:
→ Area of rectangle = 2000 * 10
→ Area of rectangle = 20000 cm²
Now, No. of rectangular plots cuts from square = area of square ÷ area of rectangle.
→ No. of plot = 100000000 ÷ 20000
→ No. of plot = 5000
Hence, 5000 rectangular plots can be cut from the square farm.
Given :-
The side of the square farm is hactometer
To Find :-
Find how many rectangular plot of length 20 m and breadth 10 meter can be cut from the farm?
Solution :-
We know that
1 hectometer = 100 m
Side of square = 1 × 100 = 100 m
Now
Area of square = side²
Area = (100)²
Area = 10000 m²
Now
Area of rectangle = Length × Breadth
Area = 20 × 10
Area = 200 m²
No. of plots = Area of square/Area of rectangle
No. of plots = 10000/200
No. of plots = 100/2
No. of plots = 50