Math, asked by susheelpatel19pes9en, 1 year ago

the side of triangle plot is in the ratio of 3:5:7 and it's perimeter is 300m . find it's area.

Answers

Answered by vishalkumar51
5
Let the side be 3x ,5x,7x
Perimeter of the Triangle=sum of all sides
3x+5x+7x=300
15x=300
x=300/15
x=20
3x=60,5x=100,7x=140
If we take base 3x and height 5x
then the area will be
area of the Triangle =1/2×base×height
1/2×60×100
300

susheelpatel19pes9en: wrong
susheelpatel19pes9en: wrong ans.
susheelpatel19pes9en: may ans .has come
susheelpatel19pes9en: and it is
susheelpatel19pes9en: 1500√3 m^2
Answered by Inflameroftheancient
26
HELLO FRIEND HERE IS YOUR ANSWER,,,,,,,,

To find the area of the triangle, we've to consider the sides of the triangle as the variables of the following sides "3a" , "5b" and "7b" which is equalling to its perimeter that is "300m"

Therefore, 3a + 5b + 7b = 300 meters

\bf{= 8a + 7a = 300 \: m}

\bf{= 15a = 300 \: m}

\bf{a = \frac{300}{15}} \\

\bf{a = 20 \: meters}

Therefore, by substituting the value of a = 20 meters into the variables of triangle sides , we get ,,,

 = > \: \: 3 \times 20 \: m \\ \\ \\ = > 60 \: m \\ \\ \\ = > \: \: 5 \times 20 \: m \\ \\ \\ = > 100 \: m \\ \\ \\ = > \: \: 7 \times 20 \: m \\ \\ \\ = > 140 \: m \\

All three sides have 60, 100 and 140 meters respectively according to their positions of sides in a triangle.

Perimeter of the triangle is = 300 meters

Therefore semi-perimeter of the triangle is =

\bf{= \frac{300}{2} \: m} \\

\bf{= 150 \: m} \\

By applying the principles and rules of Heron's formula which states the given three sides.

\boxed{\bf{Area = \sqrt{s \: (s - a) \: (s - b) \: (s - c)}}} \\

Therefore, substitute the given sides , a = 60 m, b = 100 m, c = 140 m and semi-perimeter "s" = 150 m.

\bf{Area = \sqrt{150 \: (150 - 60) \: (150 - 100) \: (150 - 140)}} \\

\bf{Area = \sqrt{150 \times 90 \times 50 \times 10}} \\

Split the values to cancel out the given value of "30" and "50" into 10 times of 5.

\bf{Area = \sqrt{30 \times 5 \: 30 \times 3 \: 5 \times 10 \times 10}} \\

Collect the terms of "30" as a square of it, terms of "5" as a square of it and , terms of "10" as a square of it. Yeah it'll work.

\bf{Area = \sqrt{30^2 \times 5^2 \times 10^2 \times 3}} \\

Cancel out the squares with square root.

\bf{Area = \sqrt{3} \: (30 \times 10 \times 5)} \\

\boxed{\bf{\therefore \: \: Area = 1500 \: \sqrt{3}}} \\

HOPE THIS HELPS YOU AND STAYS AS A REFERENCE FOR OTHER STUDENTS AND CLEARS THE DOUBTS FOR APPLYING HERON'S FORMULA!!!!!!!
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