Question

• The sides AB and AC of a triangle ABC are produced; and the bisectors of the external angles at B and C meet at P . Prove that if AB > AC, then PC > PB .

Answer 1

AB Is greater than AC (given)
LABC is greater than LACB

As LB AND LC are bisected ....
LDBP= LPBC and LPCB= LECP

As LACB is greater than LABC
LPBC is greater than LPCB
therefore PC is greater than PB
HENCE PROVED....