• The sides AB and AC of a triangle ABC are produced; and the bisectors of the external angles at B and C meet at P . Prove that if AB > AC, then PC > PB .
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AB Is greater than AC (given)
LABC is greater than LACB
As LB AND LC are bisected ....
LDBP= LPBC and LPCB= LECP
As LACB is greater than LABC
LPBC is greater than LPCB
therefore PC is greater than PB
HENCE PROVED....
LABC is greater than LACB
As LB AND LC are bisected ....
LDBP= LPBC and LPCB= LECP
As LACB is greater than LABC
LPBC is greater than LPCB
therefore PC is greater than PB
HENCE PROVED....
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