Question

The sides (in cm) of a right angled triangle containing the right angle are 5x and 3x-1.If the area of the triangle is 60 cm².find the sides of the triangle.

Answer 1

Area of rightangled triangle=1/2(5x)(3x-1)=60cm^2
3x^2-x=(60×2)/5=24
3x^2-x-24=0
b^2-4ac=(-1)^2-4(3)(-24)=1+288=289
[-(1)-+root(17)^2]/2×3]=(1+17)/6=18/6=3
(1-17)/6=-16/6

than
x=3
bc=5x=5×3=15cm
ab=3x-1=3(3)-1=9-1=8cm
ac^2=ab^2+bc^2
ac^2=(8)^2+(15)^2=64+225=289
ac^2=(17)^2
ac=17cm
sides are triangle =17cm,8cm and 15cm
please reply fast