The sides of a cuboid are in ratio 6:4:3. surface area of its faces is 432 Sq. m. find its sides.
Answers
Answered by
8
t.s.a of cuboid =2 (lb+bh+hl)
Let l=6x, b=4x, h=3x
2 (6x×4x+4x×3x+3x×6x)=432
2 (24x^2+12x^2+18x^2)=432
2×54x^2=432
108x^2=432
x^2=432/108
x^2=4
x=2
6x=6×2=12
4x=4×2=8
3x=3×2=6
Let l=6x, b=4x, h=3x
2 (6x×4x+4x×3x+3x×6x)=432
2 (24x^2+12x^2+18x^2)=432
2×54x^2=432
108x^2=432
x^2=432/108
x^2=4
x=2
6x=6×2=12
4x=4×2=8
3x=3×2=6
Answered by
3
area of cuboid = 2× ( lb+ bh+ hl)
so
let cuboid sides
6x ; 4x ; 3x
then
area = 2 ( 6x.4x+4x.3x.+3x.6x )
108x^2 = 432
so
x=2
sides are
6×2=12
4×2=8
3×2=6
so
let cuboid sides
6x ; 4x ; 3x
then
area = 2 ( 6x.4x+4x.3x.+3x.6x )
108x^2 = 432
so
x=2
sides are
6×2=12
4×2=8
3×2=6
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