Question

the sides of a rectangle are in the ratio 3:2 If it's perimeter is 40cm then find its length of a triangle​

Answer 1

Given :

• Sides : Ratio of 3:2

• Perimeter : 40cm

To Find :

• Length

Solution :

We know how to find the perimeter of a rectangle :

➜ 2( l + b)

Putting up the values we get :

➜ 40 = 2( 3x + 2x)

➜ 40 = 2×5x

➜ 40/2 = 5x

➜ 20 = 5x

➜x = 20/5

➜x = 4

When x = 4 ;

we need to substitute value of x in the ratios :

3x = 3×4 => 12cm

2x = 2×4=> 8cm

So the length: 12cm and breadth : 8cm

Let's verify the answer :

➜2( l + b)

➜ 2(12 + 8) = 40

➜ 2×20 = 40

➜ 40 = 40

LHS = RHS

Answer 2

Correct QuesTion

The sides of a rectangle are in the ratio 3:2. If it's perimeter is 40cm then find its length.

Required AnsWer

Given

Sides of a Rectangle are in the Ratio 3 : 2 And it's Perimeter is 40cm

We Find

Lenght of Given Rectangle

We Know

Perimeter of Rectangle :-

$\sf \boxed {\red{ 2\:(Length + Breadth)}}$

According to the question

We Consider length and breadth as 3x and 2x

Now, We Put the values :-

$\implies \sf { 2\:(Length + Breadth) = Perimeter}$

$\implies \sf { 2\:(3x + 2x) = 40\:cm}$

$\implies \sf { 2 × 5x = 40\:cm}$

$\implies \sf { 5x = \frac{40}{2} }$

$\implies \sf { 5x = \cancel\frac{40}{2} }$

$\implies \sf { 5x = 20 }$

$\implies \sf { x = \frac{20}{5} }$

$\implies \sf { x = \cancel\frac{20}{5} }$

$\implies \sf { x = 4\:cm }$

By Substitute the values, We Get :-

• Lenght ( 3x ) = 3 × 4 = 12 cm
• Breadth ( 2x ) = 2 × 4 = 8 cm

Hence, Lenght is 12 cm.