Question

The sides of a rectangle are in the ratio 5:7 and the perimeter of the rectangle is 96 cm. What is the area of the rectangle?

Answer 1

Let length be 7x cm ans breadth be 5x cm



Given, Perimeter of rectangle = 96

=> 2( length + breadth ) = 96

=> 7x + 5x = 48

=> 12x = 48

$= > x = \frac{48}{12} \\ \\ \mathbf{ = > \: \: x = 4}$





Sides are : 5( 4 ) = 20 cm = breadth
7( 4 ) = 28 = length




We know, Area of rectangle = length × breadth



Hence, Area = 20 × 28

Area = 560 cm²

Answer 2

Hola!!!

HERE IS THE ANSWER

Let the length and breadth of the rectangle be 7x and 5x respectively.

As we know perimeter of the rectangle = 2 (l+b) unit.

A/Q

96=2 (5x+7x) cm

96=2 (12x) cm

96=24x cm

$\frac{96}{24} cm\\ \\ = 4cm$

now length =7x = 7×4 =28 cm

and breadth = 5x =5×4=20 cm

Now area of rectangle = (l×b)sq. unit

$(28 \times 20) {cm}^{2}$

$560 {cm}^{2}$

hope it helps to you.