in the given figure ab is a diagram diameter AC is a chord and OC is a radius of a circle such that ang.BAC= 40 Find ang OCB
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angle C=90°
angle A=40°
by anles sum of a triangle in ABC
angle B=50
oc=ob both are radius
angle ocb=angle Obc
so angle ocb=50
angle A=40°
by anles sum of a triangle in ABC
angle B=50
oc=ob both are radius
angle ocb=angle Obc
so angle ocb=50
patelsakera:
thanks dinesh
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