Question

what is the no. of atoms present in 32g oxygen gas and 14g nitrogen gas?

Answer 1

Hi friend,

At First Thanks for the question,

We know,

Moler mass of O = 16u

Moler mass of O2 = 32u

And 32g of O2= 1 mole of O2

Therefore, 32 g of oxigen has molecules=
6.022×10^23

Next, 32g of O2 has atoms = 2* 6.02×10^23

2) 14g is the atomic weight of nitrogen expressed in grams = 1 mol of N atom

So, answer is = 6.022×10^23 atoms.

.....i hope it helps you

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