Question

The sides of a rectangle park are in the ratio 4 : 3.if it's area is 1728m2 , find the cost of fencing it as Rs 2.50 per metre.

Answer 1

Answer:

Step-by-step explanation:

Let the sides of rectangle be x.

Area of rectangle = l*b

=> 1728 = 4x*3x

=> 1728 = 12x²

=> 1728/12 = x²

=> 144 = x²

=> 12 = x

So, sides would be;

4x = 4*12 = 48m

3x = 3*12 = 36m

Perimeter of rectangle = 2(l+b)

=> 2(48+36)

=> 2(84)

=> 168m

Cost of fencing at Rs. 2.50 per metre.

=> 168*2.5

=> Rs. 420

Answer 2

let sides be 4x and 3x

let length=4x

breadth=3x

area of rectangular park = l*b

1728=4x* 3x

1728=12x^2

x^2=1728/12

x^2=144

x=12

length=4x

=4*12

=48cm

breadth=3x

=3*12

=36cm

perimeter of rectangle= 2(l+b)

=2(48+36)

=2(84)

=168m

cost of 1m = ₹2.50

cost of 168m=168*2.50

cost=₹420.0 ans