The sides of a rectangular park are in the ratio 4 : 3. If its area is 1728 m2, find:
(i) its perimeter
(ii) cost of fencing it at the rate of ₹40 per meter.
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Answer:
let the sides of the park be 4x and 3x
Area of the park = 1728
lenght × breadth = 1728
4x × 3x = 1728
12xsq = 1728
xsq = 1728/12
x = root 144
x = 12
therefore
lenght and breadth = 2×2×3 = 12
hence,
lenght = 4×12=48
breadth = 3×12=36
perimeter = 2(48+36)
= 2×84= 168 m
cost of fencing = rs(168×30)
=rs5040
hope it helped you
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