Question

The sides of a rectangular park are in the ratio 4:3. If its area is 2028 sq. m, find the cost of fencing
it at 3
per meter​

Answer 1

Answer:

let the ratios of sides be 4x and 4x

Area = l x b

2028 = (4x) x (3x)

2028 = 12x²

2028/12 = x²

169 = x²

13 = x

Length = 4x13

= 52m

Breadth = 3x13

= 39m

Perimeter = 2 ( 52+39)

= 2 x 91

= 182m

Cost of fencing = 182 x 3

= 546

Answer 2

Answer:

let the ratio of sides before 4x and 3x

$area = l \times b$

$2028 = 4x \times 3x$

$2028 = 12 {x}^{2}$

${x}^{2} = \frac{2028}{12}$

${x}^{2} = 169$

$x = 13$

$length = 4 \times 13 = 52m$

$breadth = 3 \times 13 = 39m$

$perimeter = 2(l + b)$

$2 \times (25 + 39)$

$2 \times 91 = 182m$

$cost \: of \: fencing = 182 \times 3 \\ \: \: \: 546$

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