The sides of a rhombus are 5 cm each and one diagonal is 8 cm . Calculate the lenght of the other diagonal and the area of rhombus plz answer
karan8560:
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Side=(1/2)*√(diagonal 1*diagonal 1+diagonal 2*diagonal 2)
Here, side=5 m and diagonal 1=8 m
After putting the above value on the formula we get,diagonal 2=6 m
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hey.. here is ur ans.. hope it helps..
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Given Side of a rhombus = 5cm.
Given Length of one diagonal = 8cm.
By Pythagoras theorem, we know that
= > (Side)^2 = (Half the diagonal1)^2 + (Half the diagonal2)^2
= > (5)^2 = (8/2)^2 + (d2)^2
= > (5)^2 = (4)^2 + (d2)^2
= > 25 = 16 + (d2)^2
= > 9 = (d2)^2
= > d2 = 3.
Therefore, the length of the other diagonal = 3 * 2 = 6cm.
We know that Area of rhombus = (1/2) * d1 * d2
= (1/2) * (8) * (6)
= 24 cm^2.
Hope this helps!
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