The sides of a right angle triangle PQR are PQ=7cm,PR=25cm and angle Q=90°respectively.Then find,tanP-tanR
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QR can be calculated using Pythagorean theorem
QR=√(PR^2-PQ^2)
=√(25^2-7^2)
=24
then
tanP=QR/PQ=24/7
tanR=PQ/QR=7/24
tanP-tan R=524/168
QR=√(PR^2-PQ^2)
=√(25^2-7^2)
=24
then
tanP=QR/PQ=24/7
tanR=PQ/QR=7/24
tanP-tan R=524/168
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32
Got it!!! CHEERS...any help jst ping m up...
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