Question

The sides of a right angled triangle are x, x+3, x+6, x being a positive integer. Find the perimeter of the triangle. give method with answer​

Answer 1

Answer:

answer is in the above attachments

Step-by-step explanation:

hope it's helpful

Answer 2

SOLUTION:-

Given

• Sides of right angled triangle are x, x+3, x+6

To find

• Perimeter of right angled triangle

Explanation

Let

• Hypotenuse = x+6

• Perpendicular = x+3

• Base = x

By Pythagoras theorem,

★ Hypotenuse² = (Perpendicular²+ Base²)

➡ (x+6)² = x² + (x+3)²

➡x²+6²+2×x×6 = x² + x²+3²+2×x×3

➡x²+36+12x= x²+x²+9+6x

➡x²-6x-27=0

➡ x²-(9-3)x-27=0

➡x²-9x+3x-27=0

➡x(x-9)+3(x-9)=0

➡ (x-9)(x+3)=0

➡x-9=0,x+3=0

➡x=9,x=-3

But side can't be negative,

So,

➡ x= 9

✔ Base = 9cm

✔ Perpendicular = x+3 = 9+3 = 12cm

✔ Hypotenuse = x+6 = 9+6 = 15cm

☆ Perimeter = Sum of all sides

➡Perimeter of triangle = 9+12+15

➡Perimeter of triangle= 36 cm

Hence,

• Perimeter of triangle will be = 36cm.

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