The sides of a right triangle whose hypotenuse is 17cm are _________ and _________
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The sides of a right triangle whose hypotenuse is 17cm are _________ and _________
For every natural number m > 1, 2m, m2 –1 and m2 + 1 form a Pythagorean triplet. Now, m2 + 1 = (2m)2 + (m2 – 1)2 Where, m2 + 1 = 17 m2 = 17 – 1 m2 = 16 m = √16 m = 4 Then, 2m = 2 × 4 = 8 And, m2 – 1 = 42 – 1 = 16 -1 = 15
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