The sides of a right truangle containing the right angle are 5x and 3x-1 if the area of the triangle is 60cm^2 ,find the sides of triangle
Answers
Answer:
Given that sides of a right-angled triangle are 5x and (3x - 1)cm.
Given that Area of the triangle = 60cm^2.
We know that Area of the triangle = 1/2 * b * h
60 = 1/2 * 5x * (3x - 1)
5x(3x - 1) = 60 * 2
5x(3x - 1) = 120
x(3x - 1) = 120/5
3x^2 - x = 24
3x^2 - x - 24 = 0
3x^2 + 8x - 9x - 24 = 0
x(3x + 8) - 3(3x + 8)
(x - 3)(3x + 8)
x = 3 (or) x = -3/8.
x value should not be -ve.Therefore the value of x = 3.
Therefore the sides of a right-angled triangle =
5x = 5 * 3 = 15cm
(3x - 1) = (3 * 3 - 1)
= 9 - 1
= 8cm
By Pythagoras theorem, we know that
h^2 = 15^2 + 8^2
= 225 + 64
= 289
h =
= 17.
Therefore the hypotenuse = 17cm.
Therefore the sides of the triangle are 8cm,15cm, and 17cm.
Hope this helps!
Read more on Brainly.in - https://brainly.in/question/2116787#readmore
Answer:
8 cm, 15 cm, 17 cm
Step-by-step explanation:
Area of right triangle = ab/2, where a and b are sides adjacent to right angle.
Here we have: a= 5x, b=3x-1, area=60 cm^2
Considering given in the formula we get:
5x*(3x-1)/2=60
3x^2-x=24
3x^2-x-24=0
Integer solution of this quadratic equation is x=3
So sides of the triangle: a=15 cm, b=8 cm
Hypotenuse of the triangle = sqrt(15^2+8^2)=17 cm