The sides of a triangle 42 cm34cm 20 cm calculat it's area and the length of the height on the longest side
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sides =42cm,34cm,20cm
so semi perimeter=(42+34+20)/2
i.e......96/2=48
area =√[s(s-a)(s-b)(s-c)]
area=√[48(48-42)(48-34)(48-20)]
area=√[48(6)(14)(28)]
area=√(2*2*2*2*3*3*2*7*2*7*2*2)
area=2*2*3*2*7*2
area=336cm²
area =½ * B*H
Base=longest side so...
336=½*42*H
336=21*H
336/21=H
16=H
so semi perimeter=(42+34+20)/2
i.e......96/2=48
area =√[s(s-a)(s-b)(s-c)]
area=√[48(48-42)(48-34)(48-20)]
area=√[48(6)(14)(28)]
area=√(2*2*2*2*3*3*2*7*2*7*2*2)
area=2*2*3*2*7*2
area=336cm²
area =½ * B*H
Base=longest side so...
336=½*42*H
336=21*H
336/21=H
16=H
golu133:
Who you solve thes question
what r u saying
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