Math, asked by AaquibAli, 1 year ago

the sides of a triangle 5cm 12cm 13cm. Find the length of the perpendicular from the opposite vertex to the side whose length is 13 cm.

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Answered by Anonymous
188

Let's say that the triangle is ABC with AB = 12, BC = 5, CA = 13.

Now you may see that triangle is right-angled at B, as AB² + BC² = CA².

And AB ⟂ BC with CA as hypotenuse and perpendicular's foot on CA be D.

Hence, ar(ABC) = ½  AB · BC = ½ CA · BD.

⇒ BD = ( AB · BC ) ÷ CA = ( 12 × 5 ) ÷ 13 = 60/13 cm. 

Answered by Anonymous
13

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