Math, asked by duttatirthankar9214, 11 months ago

The sides of a triangle are 10 cm, 24 cm and 26 cm at each of its vertices circle of radius are drawn, what is the area of the triangle excluding the portion covered by the sectors of the circles

Answers

Answered by amitnrw
2

Answer:

80.7 cm²

Step-by-step explanation:

The sides of a triangle are 10 cm, 24 cm and 26 cm at each of its vertices circle of radius are drawn, what is the area of the triangle excluding the portion covered by the sectors of the circles

The sides of a triangle are 10 cm, 24 cm and 26 cm

s = (10 + 24 + 26)/2 = 30

Area of triangle using hero rule

Area = √30(30-10)(30-24)(30-6)

= √30 * 20 * 6 * 4

= 120 cm²

Radius = 5 cm

Area covered by the sectors of the circles  = ( 180/360) π (radius)²

= (1/2) * 3.14 * 5²

= 39.3 cm²

the area of the triangle excluding the portion covered by the sectors of the circles = 120 - 39.3  = 80.7 cm²

Similar questions