The sides of a triangle are 10 cm,4.5cm,10.5cm. Find the area of the triangle using heron's formula.
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ϙᴜᴇsᴛɪᴏɴ:-
The sides of a triangle are 10 cm,4.5cm,10.5cm. Find the area of the triangle using heron's formula.
Solution:-
Given:-
- The sides of a triangle are 10 cm,4.5cm, 10.5cm
Find:-
- The area of the triangle using heron's formula.
Explanation:-
Let, In ∆ABC
- AB = 10 cm
- BC = 4.5 cm
- CA = 10.5
★Semiperimeter(S) = (AB+BC+CA)/2
➥ Semiperimeter (S) = (10+4.5+10.5)/2
➥ Semiperimeter (S) = 25/2 cm
➥ Semiperimeter (S) = 12.5 cm
Heron's Formula
★ Area of ∆ ABC = √[S(S-AB)(S-BC)(S-CA)]
➥ Area of ∆ ABC = √[12.5(12.5-10)(12.5-4.5)(12.5-10.5)]
➥ Area of ∆ ABC = √[12.5(2.5 × 8 × 2 )]
➥ Area of ∆ ABC = √[(12.5 × 40)]
➥ Area of ∆ ABC = √(500.0)
➥ Area of ∆ ABC = 10√5 cm².
Hence:-
- Area of ∆ ABC = 10√5 cm².
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