The sides of a triangle are 15,25,20 cm. Find its area
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By heron's formule,
area of a triangle=√s(s-a)(s-b)(s-c)
where s =(semi-perimeter) that is 30cm,
a=15cm(length of the first side),
b=25cm(length of the season side),
c=20cm (length of the third side)
So,
area of the triangle=√30(30-15)(30-25)(30-20)
=√30×15×5×10
=√22500
=150cm^2
Therefore,area of the triangle is 150cm^2
Hope this may help you.Thank you
area of a triangle=√s(s-a)(s-b)(s-c)
where s =(semi-perimeter) that is 30cm,
a=15cm(length of the first side),
b=25cm(length of the season side),
c=20cm (length of the third side)
So,
area of the triangle=√30(30-15)(30-25)(30-20)
=√30×15×5×10
=√22500
=150cm^2
Therefore,area of the triangle is 150cm^2
Hope this may help you.Thank you
Wreakit:
Thanks
Answered by
4
By Pythagoras therom
25*2=20*2+15*2
625=400+225
Since this sides are satisfying Pythagorean Theron therefore it is a right angled triangle
Area of triangle=1/2×20×15
Area of triangle=150cm*2
25*2=20*2+15*2
625=400+225
Since this sides are satisfying Pythagorean Theron therefore it is a right angled triangle
Area of triangle=1/2×20×15
Area of triangle=150cm*2
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