Math, asked by monikasingla8290, 10 months ago

the sides of a triangle are 30 , 16,34cm it's area is

Answers

Answered by Anonymous
2

Sides of a triangle are

a = 16 cm,

b = 30 cm

c = 34 cm

s =  \frac{(16 + 30 + 34)}{2}  \\  \:  \:  \:  \:   = \frac{80}{2}  \\  \:  \:  \:  \:   = 40 {cm}^{2}

Area of triangle = √[s(s – a)(s – b)(s – c)]

= √[40(40 – 16)(40 – 30)(40 – 34)

= √[40 × 24 × 10 × 6]

= 240 cm²

Answered by promilaningthoujam9
0

Answer:

.simi - perimeter = 30+16+34/2=80/2=40(S=A+B+C/2)

Now,

area of triangle = √s(s-a) (s-b) (s-c)

=√40(40-30)(40-16)(40-34)

=√40×10×24×6

=√57600=240cm^

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