Question

The sides of a triangle are 42 cm, 34 cm and 20 cm. Calculate it's area.​

Answer 1

Answer:

Step-by-step explanation:

use heron's formula

that states, A = √(s(s-a)(s-b)(s-c))

s=(a+b+c)/2

a,b,c are the sides of a triangle

s=(42+34+20)/2 = 48

Area = √(48(48-42)(48-34)(48-20))

Area = √(48×6×14×28)

Area = √(8×6×6×2×7×4×7)

Area = 8×6×7 = 336 cm²

Answer 2

Answer:

Sides:

a=42cm b=34cm c= 20cm

therefore

semiperimeter= a+b+c/2= 42+34+20/2

= 96/2= 48cm

By Heron's Formula

Area of triangle= √s(s-a)(s-b)(s-c)

=√48(48-42)(48-34)(48-20)

=√48(6)(14)(28)

=√2*2*2*2*3(2*3)(2*7)(2*2*7)

Here we will take the number which comes two times.Then it will come outside the root

=2*2*2*2*3*7

=336cm

This is the answer