Math, asked by nafinabeel6, 7 months ago

The sides of a triangle are 5 cm, 12 cm and 13 cm. What is its area?

Answers

Answered by rajvirsingh327
6

s=5+12+13/2

= 30/2=15cm

area of triangle (herons formula)=√s(s-a)(s-b)(s-c)

=√15(15-5)(15-12)(15-13)

=√15x10x3x2

=√3x5x2x5x3x2

=√3²x5²x2²

=3x5x2

=30cm²

Answered by Anonymous
8

Answer:

Given :

The sides of a triangle are 5 cm, 12 cm and 13 cm.

In triangle ABC,

\triangleABC,

AB,BC and AC are the sides of the triangle.

A = 5 cm

B = 12 cm

C = 13 cm.

We know that,

\frac {a+b+c}{2} = \frac {5+12+13}{2}

\frac {30}{2} = 15 \: cm

By using Heron's formula,

A = \sqrt {15(15-5)(15-12)(15-13)}

A = \sqrt {15 × 10 × 3 × 2}

\Rightarrow A = 30 cm².

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