Question

The sides of a triangle are 50cm, 78cm and 112cm find its smallest altitude?​

Answer 1

Answer:

30 cm

Step-by-step explanation:

a=50,b=78,c=112

so s=(a+b+c)/2

=(50+78+112)/2

=240/2=120 cm

Area=√[ 120(120-50)(120-78)(120-112) ]

=√(120*70*42*8)

=√2822400

=1680 cm²

=================

The smallest altitude will be to the biggest side  of length 112 cm

area= side*altitude/2

1680=112*altitude/2

altitude=1680*2/112

=30cm

Answer 2

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