The sides of a triangle are 50cm, 78cm and 112cm find its smallest altitude?
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Answer:
30 cm
Step-by-step explanation:
a=50,b=78,c=112
so s=(a+b+c)/2
=(50+78+112)/2
=240/2=120 cm
Area=√[ 120(120-50)(120-78)(120-112) ]
=√(120*70*42*8)
=√2822400
=1680 cm²
=================
The smallest altitude will be to the biggest side of length 112 cm
area= side*altitude/2
1680=112*altitude/2
altitude=1680*2/112
=30cm
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