Question

The sides of a triangle are 56cm,60cm,and 52 cm then the area of the triangle 
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Answer 1

Answer:

The area of the triangle=1344cm²

Step-by-step explanation:

Since,

The three sides of a triangle area a=56cm , b=60cm ,c=52cm

then,

semi perimeter of a triangle

$s=\frac{a+b+c}{2}$

$⇒\frac{56+60+52}{2}$

$⇒\frac{168}{2}$

$⇒84cm$

Area of a triangle

[By Heron's formula]

$⇒\sqrt{s(s-a)(s-b)(s-c)}$

$⇒\sqrt{84(84-56)(84-60)(84-52)}$

$⇒\sqrt{84×28×24×32}$

$⇒\sqrt{4×7×3×4×7×4×2×3×4×4×2}$

$⇒\sqrt{(4)^{6}×(7)^{2}×(3)^{2}}$

$⇒(4)^{3}×7×3$

$⇒1344cm^{2}$

Hence,

The area of triangle is 1344cm²

Hope it helps!

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