Question

The sides of a triangle are 5cm, 7cm and 8cm. The altitude to its smallest side is:-
a)8 √ cm b)
20/7
√ cm c) 4√ cm d) (2.5) √ cm
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Answer 1

Answer:

According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is  

A=  $\sqrt{}$s(s−a)(s−b)(s−c)

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where

s=   a+b+c/2

 = 5+7+8/2= 20/ 2 = 10CM

 

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SO , AREA For the given triangle,

A= $\sqrt{10(10-5)(10-7)(10-8)}$

$\sqrt{10*5*3*2} \\= 10\sqrt{3} CM^{2}$

 ALSO FOR SMALLEST SIDE AREA OF TRIANGLE ,

 $10\sqrt{3}$ = 1/2 *H* 5

( $10\sqrt{3}$/5 ) *2 = H

 H = $4\sqrt{3}$ cm

HOPE IT HELPS YOU :)

Step-by-step explanation:

Answer 2

Answer:

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