Question

The sides of a triangle are. 6a-3b,3a+2b,5b-2a. Find the perimeter​

Answer 1

Answer:

$perimeter \: of \: a \: trangle \: = sum \: of \: all \: sides \: \\ = (6a - 3b) + (3a + 2b) + (5b - 2a) \\ = (9a - 2a) + (7b - 3b) \\ 7a + 4b$

Answer 2

Given:

The sides of three triangle are: 6a - 3b, 3a + 2b and 5b - 2a

We have to find, the perimeter of the triangle.

Solution:

The perimeter of the triangle = Sum of all sides of the triangles

= 6a - 3b + 3a + 2b + 5b - 2a

= 7a + 4b

Thus, the perimeter of the triangle is 7a + 4b.